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## 4th grade (Eureka Math/EngageNY)

Unit 1: module 1: place value, rounding, and algorithms for addition and subtraction, unit 2: module 2: unit conversions and problem solving with metric measurement, unit 3: module 3: multi-digit multiplication and division, unit 4: module 4: angle measure and plane figures, unit 5: module 5: fraction equivalence, ordering, and operations, unit 6: module 6: decimal fractions, unit 7: module 7: exploring measurement with multiplication.

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## Eureka Math Grade 4 Module 3 Lesson 23 Answer Key

Engage ny eureka math 4th grade module 3 lesson 23 answer key, eureka math grade 4 module 3 lesson 23 problem set answer key.

Question 1. Explain your thinking or use division to answer the following. a. Is 2 a factor of 84? Answer: Yes, 2 is a factor of 84,

Explanation: 84 is a even number, 2 is a factor of every even number, ( 2 X 42 = 84).

b. Is 2 a factor of 83? Answer: No, 2 is not a factor of 83,

Explanation: 83 is a odd number, 2 is not a factor of odd numbers, So 2 is not a factor of 83, (2 X 41 = 82) and 82 + 1 = 83.

c. Is 3 a factor of 84? Answer: Yes, 3 is a factor of 84,

Explanation: 28 3| 84 -6 24 -24 0 So 3 is a factor of 84.

d. Is 2 a factor of 92? Answer: Yes, 2 is a factor of 92 and 92 is even number,

Explanation: 46 2| 92 – 8 12 -12 0 So 2 is a factor of 92.

e. Is 6 a factor of 84? Answer: Yes, 6 is a factor of 84 and 84 is even number,

Explanation: 14 6| 84 – 6 24 -24 0 So 6 is a factor of 84.

f. Is 4 a factor of 92? Answer: Yes, 4 is a factor of 92,

Explanation: 23 4| 92 – 8 12 -12 0 So 4 is a factor of 92.

g. Is 5 a factor of 84? Answer: No, 5 is not a factor of 84,

Explanation: 84 does not have 5 or 0 in ones place, all the numbers that have 5 as a factor have a 5 or 0 in ones place, So 5 is not a factor of 84.

h. Is 8 a factor of 92? Answer: No, 8 is not a factor of 92,

Explanation: 11 R4 8| 92 – 8 12 -08 04 So 8 is not a factor of 92 remainder is 4.

Question 2. Use the associative property to find more factors of 24 and 36. a. 24 = 12 × 2 = ( _4__ × 3) × 2 = __4_ × (3 × 2) = _4__ × 6 = __24_ Answer: 24 = 12 X 2 = (4 X 3) X 2 = 4 X (3 X 2) = 4 X 6 = 24,

Explanation: Used the associative property to find more factors of 24 as 24 = 12 X 2 = (4 X 3) X 2 = 4 X (3 X 2) = 4 X 6 = 24.

b. 36 = __9__ × 4 = ( __3__ × 3) × 4 = __3__ × (3 × 4) = __3__ × 12 = _36__ Answer: 36 = 9 X 4 = (3 X 3) X 4 = 3 X (3 X 4) = 3 X 12 = 36,

Explanation: Used the associative property to find more factors of 36 as 36 = 9 X 4 = (3 X 3) X 4 = 3 X (3 X 4) = 3 X 12 = 36.

Question 3. In class, we used the associative property to show that when 6 is a factor, then 2 and 3 are factors, because 6 = 2 × 3. Use the fact that 8 = 4 × 2 to show that 2 and 4 are factors of 56, 72, and 80. 56 = 8 × 7 72 = 8 × 9 80 = 8 × 10 Answer: 56 = 8 X 7 = (4 X 2) X 7 = 4 X (2 X 7) = 4 X 14 = 56,

72 = 8 X 9 = 8 X 9 = (4 X 2) X 9 = 4 X (2 X 9) = 4 X 18 = 72,

80 = 8 × 10 = 8 X 10 = (4 X 2) X 10 = 4 X (2 X 10) = 4 X 20 = 80,

Explanation: Used the fact that 8 = 4 × 2 to showed that 2 and 4 are factors of 56, 72, and 80 as

56 = 8 X 7 = (4 X 2) X 7 = 4 X (2 X 7) = 4 X 14 = 56,

80 = 8 × 10 = 8 X 10 = (4 X 2) X 10 = 4 X (2 X 10) = 4 X 20 = 80.

Question 4. The first statement is false. The second statement is true. Explain why, using words, pictures, or numbers. If a number has 2 and 4 as factors, then it has 8 as a factor. If a number has 8 as a factor, then both 2 and 4 are factors. Answer: 14 2|28 -2 08 -08 0 2 X 14 = 28, 7 4|28 -28 0 4 X 7 = 28, 3, R4 8|28 -24 04 28 has 2 and 4 as factors but not 8,

Explanation: The first statement is false. The second statement is true. If a number has 2 and 4 as factors, then it has 8 as a factor and If a number has 8 as a factor, then both 2 and 4 are factors, 14 2|28 -2 08 -08 0 2 X 14 = 28, 7 4|28 -28 0 4 X 7 = 28, 3, R4 8|28 -24 04 28 has 2 and 4 as factors but not 8, any number that can be divided exactly by 8 can also be divided by 2 and 4 instead, Since 8 = 2 X 4, Example: 8 X 5 = 40, (4 X 2) X 5 = 40.

## Eureka Math Grade 4 Module 3 Lesson 23 Exit Ticket Answer Key

Question 1. Explain your thinking or use division to answer the following. a. Is 2 a factor of 34? Answer: Yes, 2 is a factor of 34,

Explanation: 34 is a even number, 2 is a factor of every even number, (2 X 17 = 34), 17 R1 2| 34 – 2 14 -14 0 Yes, 2 is a factor of 34.

b. Is 3 a factor of 34? Answer: No, 3 is not a factor of 34,

Explanation: 11 R1 3| 34 – 3 04 -03 01 So 3 is not a factor of 34 remainder is 1.

c. Is 4 a factor of 72? Answer: Yes, 4 is a factor of 72,

Explanation: 18 4| 72 – 4 32 -32 0 So 4 is a factor of 72.

d. Is 3 a factor of 72? Answer: Yes, 3 is a factor of 72,

Explanation: 24 3| 72 – 6 12 -12 0 So 3 is a factor of 72.

Question 2. Use the associative property to explain why the following statement is true. Any number that has 9 as a factor also has 3 as a factor. Answer: Any number that has 9 as a factor also has 3 as a factor because 3 X 3 = 9,

Explanation: Let’s suppose 9 is a factor of the number N. That means N is 9 times some integer M. N = 9M, Since 9 = 3 × 3, we can also write N as N = 3 × 3 × M, That means N is 3 times some integer (3 × M). So 3 is also a factor of N.

## Eureka Math Grade 4 Module 3 Lesson 23 Homework Answer Key

Question 1. Explain your thinking or use division to answer the following. a. Is 2 a factor of 72? Answer: Yes, 2 is a factor of 72,

Explanation: 72 is a even number, 2 is a factor of every even number, (2 X 36 = 72), 36 2| 72 – 6 12 -12 0 Yes, 2 is a factor of 72.

b. Is 2 a factor of 73? Answer: No, 2 is not a factor of 73,

Explanation: 73 is a odd number, 2 is a factor of every even number not odd numbers, (2 X 36 = 72),72 + 1 = 73 36 R 1 2| 73 – 6 13 -12 1 No, 2 is not a factor of 73.

c. Is 3 a factor of 72? Answer: Yes, 2 is a factor of 72,

d. Is 2 a factor of 60? Answer: Yes, 2 is a factor of 60,

Explanation: 60 is a even number, 2 is a factor of every even number, (2 X 30 = 60), 30 2| 60 – 60 0 Yes, 2 is a factor of 60.

e. Is 6 a factor of 72? Answer: Yes, 6 is a factor of 72,

Explanation: (6 X 12 = 72), 12 6| 72 – 6 12 -12 0 Yes, 6 is a factor of 72.

f. Is 4 a factor of 60? Answer: Yes, 4 is a factor of 60,

Explanation: 60 is a even number, 4 is a factor of 60, (4 X 15 = 60), 15 4|60 -4 20 -20 0 Yes, 4 is a factor of 60.

g. Is 5 a factor of 72? Answer: No, 5 is not a factor of 72,

Explanation: 72 is a even number, 72 does not have 5 or 0 in ones place, all the numbers that have 5 as a factor have a 5 or 0 in ones place, So 5 is not a factor of 72. 14 R 2 5|72 -5 22 -20 2 No, 5 is not a factor of 72.

h. Is 8 a factor of 60? Answer: No, 8 is not a factor of 60,

Explanation: 60 is a even number, 8 is not a factor of 60, (8 X 7 = 56, remainder 4), 7 R 4 8|60 -56 04 No, 8 is not a factor of 60.

Question 2. Use the associative property to find more factors of 12 and 30. a. 12 = 6 × 2 = ( __3_ × 2) × 2 = _3__ × (2 × 2) = _3__ × _4__ = _12__ Answer: 12 = 6 X 2 = (3 X 2) X 2 = 3 X (2 X 2) = 3 X 4 = 12,

Explanation: Used the associative property to find more factors of 12 as 12 = 6 X 2 = (3 X 2) X 2 = 3 X (2 X 2) = 3 X 4 = 12.

b. 30 = __6__ × 5 = ( __2__ × 3) × 5 = __2__ × (3 × 5) = __2__ × 15 = __30__ Answer: 30 = 6 X 5 = (2 X 3) X 5 = 2 X (3 X 5) = 2 X 15 = 30,

Explanation: Used the associative property to find more factors of 30 as 30 = 6 X 5 = (2 X 3) X 5 = 2 X (3 X 5) = 2 X 15 = 30.

Question 3. In class, we used the associative property to show that when 6 is a factor, then 2 and 3 are factors, because 6 = 2 × 3. Use the fact that 10 = 5 × 2 to show that 2 and 5 are factors of 70, 80, and 90. 70 = 10 × 7 80 = 10 × 8 90 = 10 × 9 Answer: 70 = 10 X 7 = (5 X 2) X 7 = 5 X (2 X 7) = 5 X 14 = 70,

80 = 10 X 8 = 10 X 8 = (5 X 2) X 8 = 5 X (2 X 8) = 5 X 16 = 80,

90 = 10 × 9 = 10 X 9 = (5 X 2) X 9 = 5 X (2 X 9) = 5 X 18 = 90,

Explanation: Used the fact that 10 = 5 × 2 to showed that 2 and 5 are factors of 70, 80, and 90 as

70 = 10 X 7 = (5 X 2) X 7 = 5 X (2 X 7) = 5 X 14 = 70,

90 = 10 × 9 = 10 X 9 = (5 X 2) X 9 = 5 X (2 X 9) = 5 X 18 = 90.

Question 4. The first statement is false. The second statement is true. Explain why, using words, pictures, or numbers. If a number has 2 and 6 as factors, then it has 12 as a factor. If a number has 12 as a factor, then both 2 and 6 are factors. Answer: 9 2|18 -18 0 2 X 9 = 18, 3 6|18 -18 0 6 X 3 = 18, 1, R6 12|18 – 12 06 18 has 2 and 6 as factors but not 12,

Explanation: The first statement is false. The second statement is true. If a number has 2 and 6 as factors, then it has 12 as a factor and If a number has 12 as a factor, then both 2 and 6 are factors, 9 2|18 -18 0 2 X 9 = 18, 3 6|18 -18 0 6 X 3 = 18, 1, R6 12|18 – 12 06 18 has 2 and 6 as factors but not 12, any number that can be divided exactly by 12 can also be divided by 2 and 6 instead, Since 12 = 2 X 6.

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Engage NY Eureka Math 4th Grade Module 3 Lesson 1 Answer Key Eureka Math Grade 4 Module 3 Lesson 1 Problem Set Answer Key Question 1. Determine the perimeter and area of rectangles A and ... Eureka Math Grade 4 Module 3 Lesson 1 Homework Answer Key. Question 1. Determine the perimeter and area of rectangles A and B. a.

Lesson 2 Homework 4-4 3. Construct each of the following using a straightedge and/or the right angle template that you created. Explain the characteristics of each by comparing the angle to a right angle. Use the words greater than, less than, or equal to in your explanations. a. b. c. acute angle right angle obtuse angle 19 A Z VOC IS -FHA N

10 9 8 7 6 5 4 3 2 1 Eureka Math™ Grade 4, Module 6 Student File_A Contains copy-ready classwork and homework ... Lesson 1 Homework 4 6 L =L 0.3 L Name Date Shade the first 4 units of the tape diagram. Count by tenths to label the number line using a fraction and a ... ©2015 Great Minds. eureka-math.org 4 G4-M6-SE-1.3.1-11.2015.

4th grade (Eureka Math/EngageNY) 7 units · 152 skills. Unit 1. Module 1: Place value, rounding, and algorithms for addition and subtraction. Unit 2. Module 2: Unit conversions and problem solving with metric measurement. Unit 3. Module 3: Multi-digit multiplication and division. Unit 4.

EngageNY/Eureka Math Grade 4 Module 3 Lesson 1For more Eureka Math (EngageNY) videos and other resources, please visit http://EMBARC.onlinePLEASE leave a mes...

It's Homework Time! Help for fourth graders with Eureka Math Module 4 Lesson 1.

Eureka Math Grade 4 Module 4 Lesson 3 Homework Answer Key. Question 1. On each object, trace at least one pair of lines that appear to be perpendicular. Answer: Refer below to check the perpendicular angles which are traced for the images. Explanation: As two distinct lines intersect each other at 90 degrees those lines are called perpendicular ...

Grade 4 Module 3 Lessons 1-38 Eureka Math™ Homework Helper 2015-2016. 2015-16 Lesson 1 : Investigate and use the formulas for area and perimeter of rectangles. 4•3 A Story of Units G4-M3-Lesson 1 1. Determine the perimeter and area of rectangles A and B. ... 12. 4•3 1/ , /4,, , •3A Story of Units G4-M3, , ...

Eureka Math. Eureka Math® Grade 4 Module 3 TEKS EDITION Answer Key. Module 3: Multi-Digit Multiplication and Division 491 ... A STORY OF UNITS TEKS EDITION Lesson 4 Answer Key 4 • 3 Homework 1. Disks drawn; 700; 700; 7 hundreds 2. Disks drawn; 7,000; 7,000; 7 thousands 3. a. 80 b. 100 c. 8 d. 30 e. 1,000 f. 100

10 9 8 7 6 5 4 3 2 1. Eureka Math ™ Grade 4, Module 3 ... This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org . G4-M3-TE-1.3.-05.2015. 4. 4 ... Within this module, if pacing is a challenge, consider the following omissions. In Lesson 1, omit Problem 1 if you embedded it into Module 2 ...

EngageNY/Eureka Math Grade 4 Module 3 Lesson 33For more Eureka Math (EngageNY) videos and other resources, please visit http://EMBARC.onlinePLEASE leave a me...

rted License.3.E.25NYS COMMON CORE. ATHEMATICS CURRICULUMSolve us. rea model. The first. ne is done for you.Lesson 15:Date: ghts reserved. commoncore.orgLesson 15 Homework 43.E.26Understand and solve divisio. ay and area models.8/28/13This work is licensed under a Creative Common.

Answer: 4 bows can be made from 3 feet of ribbon, Left over ribbon will be 4 inches, Explanation. Given If it takes 8 inches of ribbon to make a bow, So how many bows can be made from 3 feet of ribbon. (1 foot = 12 inches) are 3 X 12 = 36 inches ÷ 8 inches =. 4 quotient (8 X 4 = 32) and 4 inches remainder means|.

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Help for fourth graders with Eureka Math Module 4 Lesson 13. It's Homework Time! Help for fourth graders with Eureka Math Module 4 Lesson 13.

Engage NY Eureka Math 4th Grade Module 3 Lesson 36 Answer Key Eureka Math Grade 4 Module 3 Lesson 36 Problem Set Answer Key. Question 1. a. In each of the two models pictured below, write the expressions that determine the area of each of the four smaller rectangles. Answer: Explanation:

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Engage NY Eureka Math 4th Grade Module 3 Lesson 16 Answer Key Eureka Math Grade 4 Module 3 Lesson 16 Problem Set Answer Key. Show the division using disks. Relate your work on the place value chart to long division. Check your quotient and remainder by using multiplication and addition. Question 1. 7 ÷ 2. quotient = ____3_____ remainder = ___1

Help for fourth graders with Eureka Math Module 1 Lesson 14. It's Homework Time! Help for fourth graders with Eureka Math Module 1 Lesson 14.

Module 3 lesson 7 homework Lesson 21 homework module 7 grade 2 Module 5 lesson 1 to 3 homework. Homework unit answers. Lesson 7 homework module 7 grade 2Lesson 5 part 1 and homework Engage ny // eureka math grade 5 module 4 lesson 7 homeworkLesson 7 homework module 3 grade 3.

Engage NY Eureka Math 4th Grade Module 3 Lesson 34 Answer Key Eureka Math Grade 4 Module 3 Lesson 34 Problem Set Answer Key. Question 1. Use the associative property to rewrite each expression. Solve using disks, and then complete the number sentences. a. 30 × 24 = ( _3___ × 10) × 24 = __3__ × (10 × 24) = ___720____ Answer: 30 X 24 = (3 X ...

Engage NY Eureka Math 4th Grade Module 3 Lesson 23 Answer Key Eureka Math Grade 4 Module 3 Lesson 23 Problem Set Answer Key. Question 1. Explain your thinking or use division to answer the following. a. Is 2 a factor of 84? Answer: Yes, 2 is a factor of 84, Explanation: 84 is a even number, 2 is a factor of every even number, ( 2 X 42 = 84). b.