Programmingoneonone
Programmingoneonone is a website that publishes daily tutorials, methods, guides, and articles on IT, Education, and technology.
HackerRank Grading Students problem solution
In this HackerRank Grading Students problem solution , HackerLand University has the following grading policy:
Every student receives a grade in the inclusive range from 0 to 100.
Any grade less than 40 is a failing grade.
Sam is a professor at the university and likes to round each student’s grade according to these rules:
If the difference between the grade and the next multiple of 5 is less than 3, round grade up to the next multiple of 5.
If the value of grade is less than 38, no rounding occurs as the result will still be a failing grade.
Problem solution in Python programming.
Problem solution in Java Programming.
Problem solution in c++ programming., problem solution in c programming., problem solution in javascript programming., related tutorials.
Comments (2) on “HackerRank Grading Students problem solution”
results = []
for grade in grades: if grade > 37: reminder = grade % 5 if reminder >= 3: grade = grade + (5 – reminder) results.append(grade)
return results
for grade in grades: number = grade%5 if grade >= 38 and number >= 3: grade = (grade+5-number) else: continue return grade
Comments are closed.
Coding Made Simple
Grading Students | HackerRank Solution
Hello coders, today we are going to solve Grading Students HackerRank Solution which is a Part of HackerRank Algorithm Series.
HackerLand University has the following grading policy:
- Every student receives a grade in the inclusive range from 0 to 100 .
- Any grade less than 40 is a failing grade.
Sam is a professor at the university and likes to round each student’s grade according to these rules:
- If the difference between the grade and the next multiple of 5 is less than 3 , round grade up to the next multiple of 5 .
- If the value of grade is less than 38 , no rounding occurs as the result will still be a failing grade.
- grade = 84 round to 85 (85 – 84 is less than 3)
- grade = 29 do not round (result is less than 40)
- grade = 57 do not round (60 – 57 is 3 or higher)
Given the initial value of grade for each of Sam’s n students, write code to automate the rounding process.
Function Description
Complete the function gradingStudents in the editor below.
gradingStudents has the following parameter(s):
- int grades[n] : the grades before rounding
- int[n] : the grades after rounding as appropriate
Input Format
The first line contains a single integer, n , the number of students. Each line i of the n subsequent lines contains a single integer, grades [ i ] .
Constraints
- 1 <= n <= 60
- 0 <= grades [ i ] <= 100
Sample Input 0
Sample Output 0
Explanation 0
- Student 1 received a 73 , and the next multiple of 5 from 73 is 75 . Since 75 – 73 < 3 , the student’s grade is rounded to 75 .
- Student 2 received a 67 , and the next multiple of 5 from 67 is 70 . Since 70 – 67 = 3 , the grade will not be modified and the student’s final grade is 67 .
- Student 3 received a 38 , and the next multiple of 5 from 38 is 40 . Since 40 – 38 < 3 , the student’s grade will be rounded to 40 .
- Student 4 received a grade below 33 , so the grade will not be modified and the student’s final grade is 33 .
Solution – Grading Students
Disclaimer: The above Problem ( Grading Students ) is generated by Hacker Rank but the Solution is Provided by CodingBroz . This tutorial is only for Educational and Learning Purpose.
Leave a Comment Cancel Reply
Your email address will not be published. Required fields are marked *
Save my name, email, and website in this browser for the next time I comment.
- Implementation
Grading Students
HackerLand University has the following grading policy:
- Every student receives a in the inclusive range from to .
- Any less than is a failing grade.
Sam is a professor at the university and likes to round each student's according to these rules:
- If the difference between the and the next multiple of is less than , round up to the next multiple of .
- If the value of is less than , no rounding occurs as the result will still be a failing grade.
- round to (85 - 84 is less than 3)
- do not round (result is less than 40)
- do not round (60 - 57 is 3 or higher)
Given the initial value of for each of Sam's students, write code to automate the rounding process.
Function Description
Complete the function gradingStudents in the editor below.
gradingStudents has the following parameter(s):
- int grades[n] : the grades before rounding
- int[n] : the grades after rounding as appropriate
Input Format
The first line contains a single integer, , the number of students. Each line of the subsequent lines contains a single integer, .
Constraints
Sample Input 0
Sample Output 0
Explanation 0
- Student received a , and the next multiple of from is . Since , the student's grade is rounded to .
- Student received a , and the next multiple of from is . Since , the grade will not be modified and the student's final grade is .
- Student received a , and the next multiple of from is . Since , the student's grade will be rounded to .
- Student received a grade below , so the grade will not be modified and the student's final grade is .
Cookie support is required to access HackerRank
Seems like cookies are disabled on this browser, please enable them to open this website
Hackerrank - Grading Students Solution
Solution in Python
Subscribe to the poor coder | algorithm solutions.
Martin Kysel
Coding Challenges and More
HackerRank 'Grading Students' Solution
Martin Kysel · May 12, 2020
Short Problem Definition:
HackerLand University has the following grading policy:
- Every student receives a grade _in__ the inclusive range from _0 to 100 .
- Any grade less than 40 is a failing grade.
Grading Students
Complexity:
time complexity is O(N)
space complexity is O(N)
Follow the problem specification. The solution could be further optimized to remove all unnecessary copies and the whole res array.
Share: Twitter , Facebook
To learn more about solving Coding Challenges in Python, I recommend these courses: Educative.io Python Algorithms , Educative.io Python Coding Interview .
Grading Students ¶
Grading Students on HackerRank
JavaScript ¶
Solution 1 ¶, solution 2 ¶.
IMAGES
VIDEO
COMMENTS
In this HackerRank Grading Students problem solution, HackerLand University has the following grading policy: Every student receives a grade in the inclusive range from 0 to 100. Any grade less than 40 is a failing grade.
Every student receives a grade in the inclusive range from 0 to 100. Any grade less than 40 is a failing grade. Sam is a professor at the university and likes to round each student’s grade according to these rules:
HackerLand University has the following grading policy: Every student receives a grade in the inclusive range from 0 to 100. Any grade less than 40 is a failing grade.
HackerRank concepts & solutions. Contribute to BlakeBrown/HackerRank-Solutions development by creating an account on GitHub.
In this quick walkthrough, I'll explain how to approach and solve the Grading Students HackerRank problem. Its difficulty rating is 'Easy', and I'll be solving it in JavaScript. ...more.
Function Description. Complete the function gradingStudents in the editor below. gradingStudents has the following parameter (s): int grades [n]: the grades before rounding. Returns. int [n]: the grades after rounding as appropriate. Input Format. The first line contains a single integer, , the number of students.
Grading Students | HackerRank Problem | Solution. Let’s understand the problem statement of grading students’ problem, this is the implementation problem by HackerRank from Algorithm’s ...
Hackerrank - Grading Students Solution. HackerLand University has the following grading policy: Every student receives a in the inclusive range from to . Any less than is a failing grade. Sam is a professor at the university and likes to round each student's according to these rules:
HackerLand University has the following grading policy: Every student receives a grade _in__ the inclusive range from _0 to 100. Any grade less than 40 is a failing grade.
Grading Students on HackerRank. JavaScript ¶. Solution 1 ¶. /** * Given some integer `num`, find its next multiple of `multiplier`. * * ASSUME: Both values are integers. * * ASSUME: The multiplier is not zero, which would cause `NaN` to * be returned.